Need help with Math hw?
Start out by making an equation: n = number of nickels n-5 = number of quarters (because you have 5 fewer than nickels) Multiply the number of each coin by its value to add up to the total of $3.85: .05n +.25(n-5) = 3.85 Distribute and solve: .05n +....
a collection of coins consists of nickels, dimes, and quarters. there are four times as many quarters as .....
since the word problem relates the number of nickels to both dimes and quarters, make X = number of nickels you have. From there, just read the problem to figure out the number of dimes and quarters.
I AM stuck Please help...?
n = nickels d = dimes .05n + .10d =2.35 n = d + 8 .05n + .10d = 2.35 n - d = 8 .05n + .10d = 2.35 .10n - .10d = 0.80 .15n = 3.15 n = 21 n= 21 => 21 - d = 8 => d = 13 Verification .05(21) + .10(13) = 2.35 1.05 + 1.30 = 2.35 2.35 = 2.35 21 - 13 = 8 8 =...