Obviously, 1 quarter. 2 dimes, 1 nickel 2 dimes, 5 pennies 1 dime, 3 nickels 1 dime, 2 nickels, 5 pennies 1 dime, 1 nickel, 10 pennies 1 dime, 15 pennies 5 nickels 4 nickels, 5 pennies 3 nickels, 10 pennies 2 nickels, 15 pennies 1 nickel, 20 pennies ...
n = nickels d = dimes .05n + .10d =2.35 n = d + 8 .05n + .10d = 2.35 n - d = 8 .05n + .10d = 2.35 .10n - .10d = 0.80 .15n = 3.15 n = 21 n= 21 => 21 - d = 8 => d = 13 Verification .05(21) + .10(13) = 2.35 1.05 + 1.30 = 2.35 2.35 = 2.35 21 - 13 = 8 8 =...
since the word problem relates the number of nickels to both dimes and quarters, make X = number of nickels you have. From there, just read the problem to figure out the number of dimes and quarters.